Whakaoti i te x^2/2=9/4

$$\frac { x ^ { 2 } } { 2 } = \frac { 9 } { 4 }$$

Whakaoti mō x

$$x = \frac{3 \sqrt{2}}{2} \approx 2.121320344$$

$$x = -\frac{3 \sqrt{2}}{2} \approx -2.121320344$$

Ngā Upane mā te Kimi Pūtakerua

Me whakarea ngā taha e rua ki te 2.

$$x^{2}=\frac{9}{4}\times 2$$

Whakareatia te \frac{9}{4} ki te 2, ka \frac{9}{2}.

$$x^{2}=\frac{9}{2}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{3\sqrt{2}}{2} x=-\frac{3\sqrt{2}}{2}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Me whakarea ngā taha e rua ki te 2.

$$x^{2}=\frac{9}{4}\times 2$$

Whakareatia te \frac{9}{4} ki te 2, ka \frac{9}{2}.

$$x^{2}=\frac{9}{2}$$

Tangohia te \frac{9}{2} mai i ngā taha e rua.

$$x^{2}-\frac{9}{2}=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -\frac{9}{2} mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-\frac{9}{2}\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-\frac{9}{2}\right)}}{2}$$

Whakareatia -4 ki te -\frac{9}{2}.

$$x=\frac{0±\sqrt{18}}{2}$$

Tuhia te pūtakerua o te 18.

$$x=\frac{0±3\sqrt{2}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±3\sqrt{2}}{2} ina he tāpiri te ±.

$$x=\frac{3\sqrt{2}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±3\sqrt{2}}{2} ina he tango te ±.

$$x=-\frac{3\sqrt{2}}{2}$$

Kua oti te whārite te whakatau.

$$x=\frac{3\sqrt{2}}{2} x=-\frac{3\sqrt{2}}{2}$$