Whakaoti i te x^2+8/(x+2)(x-2)+x/x+2-2x/x-2=

$$\frac { x ^ { 2 } + 8 } { ( x + 2 ) ( x - 2 ) } + \frac { x } { x + 2 } - \frac { 2 x } { x - 2 } =$$

Aromātai

$$\frac{2\left(4-3x\right)}{x^{2}-4}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o \left(x+2\right)\left(x-2\right) me x+2 ko \left(x-2\right)\left(x+2\right). Whakareatia \frac{x}{x+2} ki te \frac{x-2}{x-2}.

$$\frac{x^{2}+8}{\left(x-2\right)\left(x+2\right)}+\frac{x\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}-\frac{2x}{x-2}$$

Tā te mea he rite te tauraro o \frac{x^{2}+8}{\left(x-2\right)\left(x+2\right)} me \frac{x\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{x^{2}+8+x\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}-\frac{2x}{x-2}$$

Mahia ngā whakarea i roto o x^{2}+8+x\left(x-2\right).

$$\frac{x^{2}+8+x^{2}-2x}{\left(x-2\right)\left(x+2\right)}-\frac{2x}{x-2}$$

Whakakotahitia ngā kupu rite i x^{2}+8+x^{2}-2x.

$$\frac{2x^{2}+8-2x}{\left(x-2\right)\left(x+2\right)}-\frac{2x}{x-2}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o \left(x-2\right)\left(x+2\right) me x-2 ko \left(x-2\right)\left(x+2\right). Whakareatia \frac{2x}{x-2} ki te \frac{x+2}{x+2}.

$$\frac{2x^{2}+8-2x}{\left(x-2\right)\left(x+2\right)}-\frac{2x\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}$$

Tā te mea he rite te tauraro o \frac{2x^{2}+8-2x}{\left(x-2\right)\left(x+2\right)} me \frac{2x\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{2x^{2}+8-2x-2x\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}$$

Mahia ngā whakarea i roto o 2x^{2}+8-2x-2x\left(x+2\right).

$$\frac{2x^{2}+8-2x-2x^{2}-4x}{\left(x-2\right)\left(x+2\right)}$$

Whakakotahitia ngā kupu rite i 2x^{2}+8-2x-2x^{2}-4x.

$$\frac{8-6x}{\left(x-2\right)\left(x+2\right)}$$

Whakarohaina te \left(x-2\right)\left(x+2\right).

$$\frac{8-6x}{x^{2}-4}$$

Whakaroha

$$-\frac{2\left(3x-4\right)}{x^{2}-4}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o \left(x+2\right)\left(x-2\right) me x+2 ko \left(x-2\right)\left(x+2\right). Whakareatia \frac{x}{x+2} ki te \frac{x-2}{x-2}.

$$\frac{x^{2}+8}{\left(x-2\right)\left(x+2\right)}+\frac{x\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}-\frac{2x}{x-2}$$

Tā te mea he rite te tauraro o \frac{x^{2}+8}{\left(x-2\right)\left(x+2\right)} me \frac{x\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{x^{2}+8+x\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}-\frac{2x}{x-2}$$

Mahia ngā whakarea i roto o x^{2}+8+x\left(x-2\right).

$$\frac{x^{2}+8+x^{2}-2x}{\left(x-2\right)\left(x+2\right)}-\frac{2x}{x-2}$$

Whakakotahitia ngā kupu rite i x^{2}+8+x^{2}-2x.

$$\frac{2x^{2}+8-2x}{\left(x-2\right)\left(x+2\right)}-\frac{2x}{x-2}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o \left(x-2\right)\left(x+2\right) me x-2 ko \left(x-2\right)\left(x+2\right). Whakareatia \frac{2x}{x-2} ki te \frac{x+2}{x+2}.

$$\frac{2x^{2}+8-2x}{\left(x-2\right)\left(x+2\right)}-\frac{2x\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}$$

Tā te mea he rite te tauraro o \frac{2x^{2}+8-2x}{\left(x-2\right)\left(x+2\right)} me \frac{2x\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{2x^{2}+8-2x-2x\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}$$

Mahia ngā whakarea i roto o 2x^{2}+8-2x-2x\left(x+2\right).

$$\frac{2x^{2}+8-2x-2x^{2}-4x}{\left(x-2\right)\left(x+2\right)}$$

Whakakotahitia ngā kupu rite i 2x^{2}+8-2x-2x^{2}-4x.

$$\frac{8-6x}{\left(x-2\right)\left(x+2\right)}$$

Whakarohaina te \left(x-2\right)\left(x+2\right).

$$\frac{8-6x}{x^{2}-4}$$