Whakaoti i te s-7/s+3=s-9/s+5

$$\frac { s - 7 } { s + 3 } = \frac { s - 9 } { s + 5 }$$

Whakaoti mō s

$$s=2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe s ki tētahi o ngā uara -5,-3 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te \left(s+3\right)\left(s+5\right), arā, te tauraro pātahi he tino iti rawa te kitea o s+3,s+5.

$$\left(s+5\right)\left(s-7\right)=\left(s+3\right)\left(s-9\right)$$

Whakamahia te āhuatanga tuaritanga hei whakarea te s+5 ki te s-7 ka whakakotahi i ngā kupu rite.

$$s^{2}-2s-35=\left(s+3\right)\left(s-9\right)$$

Whakamahia te āhuatanga tuaritanga hei whakarea te s+3 ki te s-9 ka whakakotahi i ngā kupu rite.

$$s^{2}-2s-35=s^{2}-6s-27$$

Tangohia te s^{2} mai i ngā taha e rua.

$$s^{2}-2s-35-s^{2}=-6s-27$$

Pahekotia te s^{2} me -s^{2}, ka 0.

$$-2s-35=-6s-27$$

Me tāpiri te 6s ki ngā taha e rua.

$$-2s-35+6s=-27$$

Pahekotia te -2s me 6s, ka 4s.

$$4s-35=-27$$

Me tāpiri te 35 ki ngā taha e rua.

$$4s=-27+35$$

Tāpirihia te -27 ki te 35, ka 8.

$$4s=8$$

Whakawehea ngā taha e rua ki te 4.

$$s=\frac{8}{4}$$

Whakawehea te 8 ki te 4, kia riro ko 2.

$$s=2$$