Whakaoti i te q^9/-8*q^-3

$$\frac { q ^ { 9 } } { - 8 \cdot q ^ { - 3 } }$$

Aromātai

$$-\frac{q^{12}}{8}$$

Ngā Upane mō te Hua o ngā Pānga Taupū e Rua

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\left(q^{1}\right)^{9}\times \frac{1}{-8q^{-3}}$$

Hei hiki i te hua o ngā tau e rua, neke atu rānei ki tētahi pū, hīkina ia tau ki te pū ka tuhi ko tāna hua.

$$1^{9}\left(q^{1}\right)^{9}\times \frac{1}{-8}\times \frac{1}{q^{-3}}$$

Whakamahia te Āhuatanga Kōaro o te Whakareanga.

$$1^{9}\times \frac{1}{-8}\left(q^{1}\right)^{9}\times \frac{1}{q^{-3}}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū.

$$1^{9}\times \frac{1}{-8}q^{9}q^{-3\left(-1\right)}$$

Whakareatia -3 ki te -1.

$$1^{9}\times \frac{1}{-8}q^{9}q^{3}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$1^{9}\times \frac{1}{-8}q^{9+3}$$

Tāpirihia ngā taupū 9 me 3.

$$1^{9}\times \frac{1}{-8}q^{12}$$

Hīkina te -8 ki te pū -1.

$$-\frac{1}{8}q^{12}$$

Kimi Pārōnaki e ai ki q

$$-\frac{3q^{11}}{2}$$

Ngā Upane Otinga

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}q}(\frac{1}{-8}q^{9-\left(-3\right)})$$

Mahia ngā tātaitanga.

$$\frac{\mathrm{d}}{\mathrm{d}q}(-\frac{1}{8}q^{12})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$12\left(-\frac{1}{8}\right)q^{12-1}$$

Mahia ngā tātaitanga.

$$-\frac{3}{2}q^{11}$$