Whakaoti i te p^2/p-2+4/2-p

$$\frac { p ^ { 2 } } { p - 2 } + \frac { 4 } { 2 - p }$$

Aromātai

$$p+2$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o p-2 me 2-p ko p-2. Whakareatia \frac{4}{2-p} ki te \frac{-1}{-1}.

$$\frac{p^{2}}{p-2}+\frac{4\left(-1\right)}{p-2}$$

Tā te mea he rite te tauraro o \frac{p^{2}}{p-2} me \frac{4\left(-1\right)}{p-2}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{p^{2}+4\left(-1\right)}{p-2}$$

Mahia ngā whakarea i roto o p^{2}+4\left(-1\right).

$$\frac{p^{2}-4}{p-2}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{p^{2}-4}{p-2}.

$$\frac{\left(p-2\right)\left(p+2\right)}{p-2}$$

Me whakakore tahi te p-2 i te taurunga me te tauraro.

$$p+2$$

Kimi Pārōnaki e ai ki p

$$1$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o p-2 me 2-p ko p-2. Whakareatia \frac{4}{2-p} ki te \frac{-1}{-1}.

$$\frac{\mathrm{d}}{\mathrm{d}p}(\frac{p^{2}}{p-2}+\frac{4\left(-1\right)}{p-2})$$

Tā te mea he rite te tauraro o \frac{p^{2}}{p-2} me \frac{4\left(-1\right)}{p-2}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}p}(\frac{p^{2}+4\left(-1\right)}{p-2})$$

Mahia ngā whakarea i roto o p^{2}+4\left(-1\right).

$$\frac{\mathrm{d}}{\mathrm{d}p}(\frac{p^{2}-4}{p-2})$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{p^{2}-4}{p-2}.

$$\frac{\mathrm{d}}{\mathrm{d}p}(\frac{\left(p-2\right)\left(p+2\right)}{p-2})$$

Me whakakore tahi te p-2 i te taurunga me te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}p}(p+2)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$p^{1-1}$$

Tango 1 mai i 1.

$$p^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$1$$