Whakaoti i te p+5/p-1=p+2/p-2

$$\frac { p + 5 } { p - 1 } = \frac { p + 2 } { p - 2 }$$

Whakaoti mō p

$$p=4$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe p ki tētahi o ngā uara 1,2 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te \left(p-2\right)\left(p-1\right), arā, te tauraro pātahi he tino iti rawa te kitea o p-1,p-2.

$$\left(p-2\right)\left(p+5\right)=\left(p-1\right)\left(p+2\right)$$

Whakamahia te āhuatanga tuaritanga hei whakarea te p-2 ki te p+5 ka whakakotahi i ngā kupu rite.

$$p^{2}+3p-10=\left(p-1\right)\left(p+2\right)$$

Whakamahia te āhuatanga tuaritanga hei whakarea te p-1 ki te p+2 ka whakakotahi i ngā kupu rite.

$$p^{2}+3p-10=p^{2}+p-2$$

Tangohia te p^{2} mai i ngā taha e rua.

$$p^{2}+3p-10-p^{2}=p-2$$

Pahekotia te p^{2} me -p^{2}, ka 0.

$$3p-10=p-2$$

Tangohia te p mai i ngā taha e rua.

$$3p-10-p=-2$$

Pahekotia te 3p me -p, ka 2p.

$$2p-10=-2$$

Me tāpiri te 10 ki ngā taha e rua.

$$2p=-2+10$$

Tāpirihia te -2 ki te 10, ka 8.

$$2p=8$$

Whakawehea ngā taha e rua ki te 2.

$$p=\frac{8}{2}$$

Whakawehea te 8 ki te 2, kia riro ko 4.

$$p=4$$