Whakaoti i te k/2x-4-1=x/1-2

$$\frac { k } { 2 x - 4 } - 1 = \frac { x } { 1 - 2 }$$

Whakaoti mō k

$$k=-2\left(x-2\right)\left(x-1\right)$$

$$x\neq 2$$

Ngā Upane Otinga

Whakareatia ngā taha e rua o te whārite ki te 2\left(x-2\right).

$$k+2\left(x-2\right)\left(-1\right)=\left(-2x+4\right)x$$

Whakareatia te 2 ki te -1, ka -2.

$$k-2\left(x-2\right)=\left(-2x+4\right)x$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2 ki te x-2.

$$k-2x+4=\left(-2x+4\right)x$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2x+4 ki te x.

$$k-2x+4=-2x^{2}+4x$$

Me tāpiri te 2x ki ngā taha e rua.

$$k+4=-2x^{2}+4x+2x$$

Pahekotia te 4x me 2x, ka 6x.

$$k+4=-2x^{2}+6x$$

Tangohia te 4 mai i ngā taha e rua.

$$k=-2x^{2}+6x-4$$

Whakaoti mō x (complex solution)

$$\left\{\begin{matrix}\\x=\frac{-\sqrt{1-2k}+3}{2}\text{, }&\text{unconditionally}\\x=\frac{\sqrt{1-2k}+3}{2}\text{, }&k\neq 0\end{matrix}\right.$$

Whakaoti mō x

$$\left\{\begin{matrix}x=\frac{-\sqrt{1-2k}+3}{2}\text{, }&k\leq \frac{1}{2}\\x=\frac{\sqrt{1-2k}+3}{2}\text{, }&k\neq 0\text{ and }k\leq \frac{1}{2}\end{matrix}\right.$$