Whakaoti i te k^2+15k+56/3k+21divk+8/10

$$\frac { k ^ { 2 } + 15 k + 56 } { 3 k + 21 } \div \frac { k + 8 } { 10 }$$

Aromātai

$$\frac{10}{3}\approx 3.333333333$$

Ngā Hipanga Rongoā Poto

Whakawehe \frac{k^{2}+15k+56}{3k+21} ki te \frac{k+8}{10} mā te whakarea \frac{k^{2}+15k+56}{3k+21} ki te tau huripoki o \frac{k+8}{10}.

$$\frac{\left(k^{2}+15k+56\right)\times 10}{\left(3k+21\right)\left(k+8\right)}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{10\left(k+7\right)\left(k+8\right)}{3\left(k+7\right)\left(k+8\right)}$$

Me whakakore tahi te \left(k+7\right)\left(k+8\right) i te taurunga me te tauraro.

$$\frac{10}{3}$$

Tauwehe

$$\frac{2 \cdot 5}{3} = 3\frac{1}{3} = 3.3333333333333335$$