Whakaoti i te k^-36*k^9/k^6*k^0

$$\frac { k ^ { - 36 } \cdot k ^ { 9 } } { k ^ { 6 } \cdot k ^ { 0 } }$$

Aromātai

$$\frac{1}{k^{33}}$$

Ngā Upane Otinga

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te -36 me te 9 kia riro ai te -27.

$$\frac{k^{-27}}{k^{6}k^{0}}$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 6 me te 0 kia riro ai te 6.

$$\frac{k^{-27}}{k^{6}}$$

Tuhia anō te k^{6} hei k^{-27}k^{33}. Me whakakore tahi te k^{-27} i te taurunga me te tauraro.

$$\frac{1}{k^{33}}$$

Kimi Pārōnaki e ai ki k

$$-\frac{33}{k^{34}}$$

Ngā Upane e Whakamahi ana i te Ture Mekameka

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te -36 me te 9 kia riro ai te -27.

$$\frac{\mathrm{d}}{\mathrm{d}k}(\frac{k^{-27}}{k^{6}k^{0}})$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 6 me te 0 kia riro ai te 6.

$$\frac{\mathrm{d}}{\mathrm{d}k}(\frac{k^{-27}}{k^{6}})$$

Tuhia anō te k^{6} hei k^{-27}k^{33}. Me whakakore tahi te k^{-27} i te taurunga me te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}k}(\frac{1}{k^{33}})$$

Mēnā ko F te hanganga o ngā pānga e rua e taea ana te pārōnaki f\left(u\right) me u=g\left(x\right), arā, mēnā ko F\left(x\right)=f\left(g\left(x\right)\right), ko te pārōnaki o F te pārōnaki o f e ai ki u whakareatia te pārōnaki o g e ai ki x, arā, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$-\left(k^{33}\right)^{-1-1}\frac{\mathrm{d}}{\mathrm{d}k}(k^{33})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$-\left(k^{33}\right)^{-2}\times 33k^{33-1}$$

Whakarūnātia.

$$-33k^{32}\left(k^{33}\right)^{-2}$$