Whakaoti i te j^-29/j^-7*j^-9

$$\frac { j ^ { - 29 } } { j ^ { - 7 } \cdot j ^ { - 9 } }$$

Aromātai

$$\frac{1}{j^{13}}$$

Ngā Upane Otinga

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te -7 me te -9 kia riro ai te -16.

$$\frac{j^{-29}}{j^{-16}}$$

Tuhia anō te j^{-16} hei j^{-29}j^{13}. Me whakakore tahi te j^{-29} i te taurunga me te tauraro.

$$\frac{1}{j^{13}}$$

Kimi Pārōnaki e ai ki j

$$-\frac{13}{j^{14}}$$

Ngā Upane e Whakamahi ana i te Ture Mekameka

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te -7 me te -9 kia riro ai te -16.

$$\frac{\mathrm{d}}{\mathrm{d}j}(\frac{j^{-29}}{j^{-16}})$$

Tuhia anō te j^{-16} hei j^{-29}j^{13}. Me whakakore tahi te j^{-29} i te taurunga me te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}j}(\frac{1}{j^{13}})$$

Mēnā ko F te hanganga o ngā pānga e rua e taea ana te pārōnaki f\left(u\right) me u=g\left(x\right), arā, mēnā ko F\left(x\right)=f\left(g\left(x\right)\right), ko te pārōnaki o F te pārōnaki o f e ai ki u whakareatia te pārōnaki o g e ai ki x, arā, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$-\left(j^{13}\right)^{-1-1}\frac{\mathrm{d}}{\mathrm{d}j}(j^{13})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$-\left(j^{13}\right)^{-2}\times 13j^{13-1}$$

Whakarūnātia.

$$-13j^{12}\left(j^{13}\right)^{-2}$$