Whakaoti i te i(3+4i)/(3-4i)(3+4i)

$$\frac { i ( 3 + 4 i ) } { ( 3 - 4 i ) ( 3 + 4 i ) }$$

Aromātai

$$-\frac{4}{25}+\frac{3}{25}i=-0.16+0.12i$$

Ngā Upane Otinga

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{i\left(3+4i\right)}{3^{2}-4^{2}i^{2}}$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$\frac{i\left(3+4i\right)}{25}$$

Whakareatia i ki te 3+4i.

$$\frac{3i+4i^{2}}{25}$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$\frac{3i+4\left(-1\right)}{25}$$

Mahia ngā whakarea i roto o 3i+4\left(-1\right). Whakaraupapatia anō ngā kīanga tau.

$$\frac{-4+3i}{25}$$

Whakawehea te -4+3i ki te 25, kia riro ko -\frac{4}{25}+\frac{3}{25}i.

$$-\frac{4}{25}+\frac{3}{25}i$$

Wāhi Tūturu

$$-\frac{4}{25} = -0.16$$

Ngā Upane Otinga

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$Re(\frac{i\left(3+4i\right)}{3^{2}-4^{2}i^{2}})$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$Re(\frac{i\left(3+4i\right)}{25})$$

Whakareatia i ki te 3+4i.

$$Re(\frac{3i+4i^{2}}{25})$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$Re(\frac{3i+4\left(-1\right)}{25})$$

Mahia ngā whakarea i roto o 3i+4\left(-1\right). Whakaraupapatia anō ngā kīanga tau.

$$Re(\frac{-4+3i}{25})$$

Whakawehea te -4+3i ki te 25, kia riro ko -\frac{4}{25}+\frac{3}{25}i.

$$Re(-\frac{4}{25}+\frac{3}{25}i)$$

Ko te wāhi tūturu o -\frac{4}{25}+\frac{3}{25}i ko -\frac{4}{25}.

$$-\frac{4}{25}$$