Whakaoti i te d/dx(x-1)(x-2)(x-3)

$$\frac { d } { d x } ( x - 1 ) ( x - 2 ) ( x - 3 )$$

Aromātai

$$3x^{2}-12x+11$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o x-1 ki ia tau o x-2.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\left(x^{2}-2x-x+2\right)\left(x-3\right))$$

Pahekotia te -2x me -x, ka -3x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\left(x^{2}-3x+2\right)\left(x-3\right))$$

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o x^{2}-3x+2 ki ia tau o x-3.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{3}-3x^{2}-3x^{2}+9x+2x-6)$$

Pahekotia te -3x^{2} me -3x^{2}, ka -6x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{3}-6x^{2}+9x+2x-6)$$

Pahekotia te 9x me 2x, ka 11x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{3}-6x^{2}+11x-6)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3x^{3-1}+2\left(-6\right)x^{2-1}+11x^{1-1}$$

Tango 1 mai i 3.

$$3x^{2}+2\left(-6\right)x^{2-1}+11x^{1-1}$$

Whakareatia 2 ki te -6.

$$3x^{2}-12x^{2-1}+11x^{1-1}$$

Tango 1 mai i 2.

$$3x^{2}-12x^{1}+11x^{1-1}$$

Tango 1 mai i 1.

$$3x^{2}-12x^{1}+11x^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$3x^{2}-12x+11x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$3x^{2}-12x+11\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$3x^{2}-12x+11$$

Kimi Pārōnaki e ai ki x

$$6\left(x-2\right)$$