Whakaoti i te d/dt(t^2-1/2t)

$$\frac { d } { d t } ( \frac { t ^ { 2 } - 1 } { 2 t } )$$

Aromātai

$$\frac{1}{2}+\frac{1}{2t^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{2t^{1}\frac{\mathrm{d}}{\mathrm{d}t}(t^{2}-1)-\left(t^{2}-1\right)\frac{\mathrm{d}}{\mathrm{d}t}(2t^{1})}{\left(2t^{1}\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{2t^{1}\times 2t^{2-1}-\left(t^{2}-1\right)\times 2t^{1-1}}{\left(2t^{1}\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{2t^{1}\times 2t^{1}-\left(t^{2}-1\right)\times 2t^{0}}{\left(2t^{1}\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{2t^{1}\times 2t^{1}-\left(t^{2}\times 2t^{0}-2t^{0}\right)}{\left(2t^{1}\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{2\times 2t^{1+1}-\left(2t^{2}-2t^{0}\right)}{\left(2t^{1}\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{4t^{2}-\left(2t^{2}-2t^{0}\right)}{\left(2t^{1}\right)^{2}}$$

Tangohia ngā taiapa kāore i te hiahiatia.

$$\frac{4t^{2}-2t^{2}-\left(-2t^{0}\right)}{\left(2t^{1}\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(4-2\right)t^{2}-\left(-2t^{0}\right)}{\left(2t^{1}\right)^{2}}$$

Tango 2 mai i 4.

$$\frac{2t^{2}-\left(-2t^{0}\right)}{\left(2t^{1}\right)^{2}}$$

Tauwehea te 2.

$$\frac{2\left(t^{2}-\left(-t^{0}\right)\right)}{\left(2t^{1}\right)^{2}}$$

Hei hiki i te hua o ngā tau e rua, neke atu rānei ki tētahi pū, hīkina ia tau ki te pū ka tuhi ko tāna hua.

$$\frac{2\left(t^{2}-\left(-t^{0}\right)\right)}{2^{2}t^{2}}$$

Hīkina te 2 ki te pū 2.

$$\frac{2\left(t^{2}-\left(-t^{0}\right)\right)}{4t^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{2\left(t^{2}-\left(-1\right)\right)}{4t^{2}}$$

Kimi Pārōnaki e ai ki t

$$-\frac{1}{t^{3}}$$