\frac { d ^ { 2 } y } { d x } + d y = 1
Whakaoti mō d
d=\frac{1}{y}
y\neq 0
Whakaoti mō x (complex solution)
x\in \mathrm{C}
d=\frac{1}{y}\text{ and }y\neq 0
Whakaoti mō x
x\in \mathrm{R}
d=\frac{1}{y}\text{ and }y\neq 0
Tohaina
Kua tāruatia ki te papatopenga
dy=1-\frac{\mathrm{d}(y)}{\mathrm{d}x}
Tangohia te \frac{\mathrm{d}(y)}{\mathrm{d}x} mai i ngā taha e rua.
yd=1
He hanga arowhānui tō te whārite.
\frac{yd}{y}=\frac{1}{y}
Whakawehea ngā taha e rua ki te y.
d=\frac{1}{y}
Mā te whakawehe ki te y ka wetekia te whakareanga ki te y.
Ngā Tauira
whārite tapawhā
{ x } ^ { 2 } - 4 x - 5 = 0
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\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
whārite Simultaneous
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Ngā Tepe
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