Whakaoti i te b^85/b^31*b^90

$$\frac { b ^ { 85 } } { b ^ { 31 } \cdot b ^ { 90 } }$$

Aromātai

$$\frac{1}{b^{36}}$$

Ngā Upane Otinga

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 31 me te 90 kia riro ai te 121.

$$\frac{b^{85}}{b^{121}}$$

Tuhia anō te b^{121} hei b^{85}b^{36}. Me whakakore tahi te b^{85} i te taurunga me te tauraro.

$$\frac{1}{b^{36}}$$

Kimi Pārōnaki e ai ki b

$$-\frac{36}{b^{37}}$$

Ngā Upane e Whakamahi ana i te Ture Mekameka

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 31 me te 90 kia riro ai te 121.

$$\frac{\mathrm{d}}{\mathrm{d}b}(\frac{b^{85}}{b^{121}})$$

Tuhia anō te b^{121} hei b^{85}b^{36}. Me whakakore tahi te b^{85} i te taurunga me te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}b}(\frac{1}{b^{36}})$$

Mēnā ko F te hanganga o ngā pānga e rua e taea ana te pārōnaki f\left(u\right) me u=g\left(x\right), arā, mēnā ko F\left(x\right)=f\left(g\left(x\right)\right), ko te pārōnaki o F te pārōnaki o f e ai ki u whakareatia te pārōnaki o g e ai ki x, arā, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$-\left(b^{36}\right)^{-1-1}\frac{\mathrm{d}}{\mathrm{d}b}(b^{36})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$-\left(b^{36}\right)^{-2}\times 36b^{36-1}$$

Whakarūnātia.

$$-36b^{35}\left(b^{36}\right)^{-2}$$