Whakaoti i te b^2+2/b^4-1+3/1-b^4

$$\frac { b ^ { 2 } + 2 } { b ^ { 4 } - 1 } + \frac { 3 } { 1 - b ^ { 4 } }$$

Aromātai

$$\frac{1}{b^{2}+1}$$

Ngā Hipanga Rongoā Poto

Tauwehea te b^{4}-1. Tauwehea te 1-b^{4}.

$$\frac{b^{2}+2}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)}+\frac{3}{\left(b-1\right)\left(b+1\right)\left(-b^{2}-1\right)}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o \left(b-1\right)\left(b+1\right)\left(b^{2}+1\right) me \left(b-1\right)\left(b+1\right)\left(-b^{2}-1\right) ko \left(b-1\right)\left(b+1\right)\left(b^{2}+1\right). Whakareatia \frac{3}{\left(b-1\right)\left(b+1\right)\left(-b^{2}-1\right)} ki te \frac{-1}{-1}.

$$\frac{b^{2}+2}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)}+\frac{3\left(-1\right)}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)}$$

Tā te mea he rite te tauraro o \frac{b^{2}+2}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)} me \frac{3\left(-1\right)}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{b^{2}+2+3\left(-1\right)}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)}$$

Mahia ngā whakarea i roto o b^{2}+2+3\left(-1\right).

$$\frac{b^{2}+2-3}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)}$$

Whakakotahitia ngā kupu rite i b^{2}+2-3.

$$\frac{b^{2}-1}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{b^{2}-1}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)}.

$$\frac{\left(b-1\right)\left(b+1\right)}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)}$$

Me whakakore tahi te \left(b-1\right)\left(b+1\right) i te taurunga me te tauraro.

$$\frac{1}{b^{2}+1}$$

Whakaroha

$$\frac{1}{b^{2}+1}$$

Ngā Hipanga Rongoā Poto

Tauwehea te b^{4}-1. Tauwehea te 1-b^{4}.

$$\frac{b^{2}+2}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)}+\frac{3}{\left(b-1\right)\left(b+1\right)\left(-b^{2}-1\right)}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o \left(b-1\right)\left(b+1\right)\left(b^{2}+1\right) me \left(b-1\right)\left(b+1\right)\left(-b^{2}-1\right) ko \left(b-1\right)\left(b+1\right)\left(b^{2}+1\right). Whakareatia \frac{3}{\left(b-1\right)\left(b+1\right)\left(-b^{2}-1\right)} ki te \frac{-1}{-1}.

$$\frac{b^{2}+2}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)}+\frac{3\left(-1\right)}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)}$$

Tā te mea he rite te tauraro o \frac{b^{2}+2}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)} me \frac{3\left(-1\right)}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{b^{2}+2+3\left(-1\right)}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)}$$

Mahia ngā whakarea i roto o b^{2}+2+3\left(-1\right).

$$\frac{b^{2}+2-3}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)}$$

Whakakotahitia ngā kupu rite i b^{2}+2-3.

$$\frac{b^{2}-1}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{b^{2}-1}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)}.

$$\frac{\left(b-1\right)\left(b+1\right)}{\left(b-1\right)\left(b+1\right)\left(b^{2}+1\right)}$$

Me whakakore tahi te \left(b-1\right)\left(b+1\right) i te taurunga me te tauraro.

$$\frac{1}{b^{2}+1}$$