Whakaoti i te a-1/3a5/6aa+2/a^2=

$$\frac { a - 1 } { 3 a } \frac { 5 } { 6 a } \frac { a + 2 } { a ^ { 2 } } =$$

Aromātai

$$\frac{5\left(a-1\right)\left(a+2\right)}{18a^{4}}$$

Ngā Hipanga Rongoā Poto

Me whakarea te \frac{a-1}{3a} ki te \frac{5}{6a} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\left(a-1\right)\times 5}{3a\times 6a}\times \frac{a+2}{a^{2}}$$

Me whakarea te \frac{\left(a-1\right)\times 5}{3a\times 6a} ki te \frac{a+2}{a^{2}} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\left(a-1\right)\times 5\left(a+2\right)}{3a\times 6aa^{2}}$$

Whakareatia te a ki te a, ka a^{2}.

$$\frac{\left(a-1\right)\times 5\left(a+2\right)}{3a^{2}\times 6a^{2}}$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 2 me te 2 kia riro ai te 4.

$$\frac{\left(a-1\right)\times 5\left(a+2\right)}{3a^{4}\times 6}$$

Whakareatia te 3 ki te 6, ka 18.

$$\frac{\left(a-1\right)\times 5\left(a+2\right)}{18a^{4}}$$

Whakamahia te āhuatanga tohatoha hei whakarea te a-1 ki te 5.

$$\frac{\left(5a-5\right)\left(a+2\right)}{18a^{4}}$$

Whakamahia te āhuatanga tuaritanga hei whakarea te 5a-5 ki te a+2 ka whakakotahi i ngā kupu rite.

$$\frac{5a^{2}+5a-10}{18a^{4}}$$

Whakaroha

$$\frac{5\left(a^{2}+a-2\right)}{18a^{4}}$$

Ngā Hipanga Rongoā Poto

Me whakarea te \frac{a-1}{3a} ki te \frac{5}{6a} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\left(a-1\right)\times 5}{3a\times 6a}\times \frac{a+2}{a^{2}}$$

Me whakarea te \frac{\left(a-1\right)\times 5}{3a\times 6a} ki te \frac{a+2}{a^{2}} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\left(a-1\right)\times 5\left(a+2\right)}{3a\times 6aa^{2}}$$

Whakareatia te a ki te a, ka a^{2}.

$$\frac{\left(a-1\right)\times 5\left(a+2\right)}{3a^{2}\times 6a^{2}}$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 2 me te 2 kia riro ai te 4.

$$\frac{\left(a-1\right)\times 5\left(a+2\right)}{3a^{4}\times 6}$$

Whakareatia te 3 ki te 6, ka 18.

$$\frac{\left(a-1\right)\times 5\left(a+2\right)}{18a^{4}}$$

Whakamahia te āhuatanga tohatoha hei whakarea te a-1 ki te 5.

$$\frac{\left(5a-5\right)\left(a+2\right)}{18a^{4}}$$

Whakamahia te āhuatanga tuaritanga hei whakarea te 5a-5 ki te a+2 ka whakakotahi i ngā kupu rite.

$$\frac{5a^{2}+5a-10}{18a^{4}}$$