Whakaoti i te a/2+2a^2/3-4a^3/4=

$$\frac { a } { 2 } + \frac { 2 a ^ { 2 } } { 3 } - \frac { 4 a ^ { 3 } } { 4 } =$$

Aromātai

$$-a^{3}+\frac{2a^{2}}{3}+\frac{a}{2}$$

Ngā Hipanga Rongoā Poto

Me whakakore te 4 me te 4.

$$\frac{a}{2}+\frac{2a^{2}}{3}-a^{3}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o 2 me 3 ko 6. Whakareatia \frac{a}{2} ki te \frac{3}{3}. Whakareatia \frac{2a^{2}}{3} ki te \frac{2}{2}.

$$\frac{3a}{6}+\frac{2\times 2a^{2}}{6}-a^{3}$$

Tā te mea he rite te tauraro o \frac{3a}{6} me \frac{2\times 2a^{2}}{6}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{3a+2\times 2a^{2}}{6}-a^{3}$$

Mahia ngā whakarea i roto o 3a+2\times 2a^{2}.

$$\frac{3a+4a^{2}}{6}-a^{3}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia a^{3} ki te \frac{6}{6}.

$$\frac{3a+4a^{2}}{6}-\frac{6a^{3}}{6}$$

Tā te mea he rite te tauraro o \frac{3a+4a^{2}}{6} me \frac{6a^{3}}{6}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{3a+4a^{2}-6a^{3}}{6}$$

Whakawehea ia wā o 3a+4a^{2}-6a^{3} ki te 6, kia riro ko \frac{1}{2}a-a^{3}+\frac{2}{3}a^{2}.

$$\frac{1}{2}a-a^{3}+\frac{2}{3}a^{2}$$

Tauwehe

$$-a\left(a-\left(-\frac{\sqrt{22}}{6}+\frac{1}{3}\right)\right)\left(a-\left(\frac{\sqrt{22}}{6}+\frac{1}{3}\right)\right)$$