Whakaoti i te a/2^3(64)-12adiv6

$$\frac { a } { 2 ^ { 3 } } ( 64 ) - 12 a \div 6$$

Aromātai

$$6a$$

Ngā Upane Otinga

Tātaihia te 2 mā te pū o 3, kia riro ko 8.

$$\frac{a}{8}\times 64-\frac{12a}{6}$$

Whakakorea atu te tauwehe pūnoa nui rawa 8 i roto i te 64 me te 8.

$$8a-\frac{12a}{6}$$

Whakawehea te 12a ki te 6, kia riro ko 2a.

$$8a-2a$$

Pahekotia te 8a me -2a, ka 6a.

$$6a$$

Kimi Pārōnaki e ai ki a

$$6$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Pārōnaki

Tātaihia te 2 mā te pū o 3, kia riro ko 8.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{a}{8}\times 64-\frac{12a}{6})$$

Whakakorea atu te tauwehe pūnoa nui rawa 8 i roto i te 64 me te 8.

$$\frac{\mathrm{d}}{\mathrm{d}a}(8a-\frac{12a}{6})$$

Whakawehea te 12a ki te 6, kia riro ko 2a.

$$\frac{\mathrm{d}}{\mathrm{d}a}(8a-2a)$$

Pahekotia te 8a me -2a, ka 6a.

$$\frac{\mathrm{d}}{\mathrm{d}a}(6a)$$

Ko te pārōnaki o ax^{n} ko nax^{n-1}.

$$6a^{1-1}$$

Tango 1 mai i 1.

$$6a^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$6\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$6$$