Whakaoti i te a^2/36+frac{(sqrt{15+3})^2}{9}=1

$$\frac { a ^ { 2 } } { 36 } + \frac { ( \sqrt { 15 + 3 } ) ^ { 2 } } { 9 } = 1$$

Whakaoti mō a

$$a=-6i$$

$$a=6i$$

Ngā Upane mā te Kimi Pūtakerua

Me whakarea ngā taha e rua o te whārite ki te 36, arā, te tauraro pātahi he tino iti rawa te kitea o 36,9.

$$a^{2}+4\left(\sqrt{15+3}\right)^{2}=36$$

Tāpirihia te 15 ki te 3, ka 18.

$$a^{2}+4\left(\sqrt{18}\right)^{2}=36$$

Ko te pūrua o \sqrt{18} ko 18.

$$a^{2}+4\times 18=36$$

Whakareatia te 4 ki te 18, ka 72.

$$a^{2}+72=36$$

Tangohia te 72 mai i ngā taha e rua.

$$a^{2}=36-72$$

Tangohia te 72 i te 36, ka -36.

$$a^{2}=-36$$

Kua oti te whārite te whakatau.

$$a=6i a=-6i$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Me whakarea ngā taha e rua o te whārite ki te 36, arā, te tauraro pātahi he tino iti rawa te kitea o 36,9.

$$a^{2}+4\left(\sqrt{15+3}\right)^{2}=36$$

Tāpirihia te 15 ki te 3, ka 18.

$$a^{2}+4\left(\sqrt{18}\right)^{2}=36$$

Ko te pūrua o \sqrt{18} ko 18.

$$a^{2}+4\times 18=36$$

Whakareatia te 4 ki te 18, ka 72.

$$a^{2}+72=36$$

Tangohia te 36 mai i ngā taha e rua.

$$a^{2}+72-36=0$$

Tangohia te 36 i te 72, ka 36.

$$a^{2}+36=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me 36 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$a=\frac{0±\sqrt{0^{2}-4\times 36}}{2}$$

Pūrua 0.

$$a=\frac{0±\sqrt{-4\times 36}}{2}$$

Whakareatia -4 ki te 36.

$$a=\frac{0±\sqrt{-144}}{2}$$

Tuhia te pūtakerua o te -144.

$$a=\frac{0±12i}{2}$$

Nā, me whakaoti te whārite a=\frac{0±12i}{2} ina he tāpiri te ±.

$$a=6i$$

Nā, me whakaoti te whārite a=\frac{0±12i}{2} ina he tango te ±.

$$a=-6i$$

Kua oti te whārite te whakatau.

$$a=6i a=-6i$$