Whakaoti i te a^2+b^2/ab=a+c/b

$$\frac { a ^ { 2 } + b ^ { 2 } } { a b } = \frac { a + c } { b }$$

Whakaoti mō a

$$a=\frac{b^{2}}{c}$$

$$b\neq 0\text{ and }c\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe a ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te ab, arā, te tauraro pātahi he tino iti rawa te kitea o ab,b.

$$a^{2}+b^{2}=a\left(a+c\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te a ki te a+c.

$$a^{2}+b^{2}=a^{2}+ac$$

Tangohia te a^{2} mai i ngā taha e rua.

$$a^{2}+b^{2}-a^{2}=ac$$

Pahekotia te a^{2} me -a^{2}, ka 0.

$$b^{2}=ac$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$ac=b^{2}$$

He hanga arowhānui tō te whārite.

$$ca=b^{2}$$

Whakawehea ngā taha e rua ki te c.

$$\frac{ca}{c}=\frac{b^{2}}{c}$$

Mā te whakawehe ki te c ka wetekia te whakareanga ki te c.

$$a=\frac{b^{2}}{c}$$

Tē taea kia ōrite te tāupe a ki 0.

$$a=\frac{b^{2}}{c}\text{, }a\neq 0$$

Whakaoti mō b (complex solution)

$$b=-\sqrt{a}\sqrt{c}$$

$$b=\sqrt{a}\sqrt{c}\text{, }a\neq 0\text{ and }c\neq 0$$

Whakaoti mō b

$$b=\sqrt{ac}$$

$$b=-\sqrt{ac}\text{, }\left(c<0\text{ and }a<0\right)\text{ or }\left(a>0\text{ and }c>0\right)$$