Whakaoti i te Y(s)/U(s)=1/s(s+1)(s+2)

$$\frac { Y ( s ) } { U ( s ) } = \frac { 1 } { s ( s + 1 ) ( s + 2 ) }$$

Whakaoti mō Y

$$Y=\frac{U}{s\left(s+1\right)\left(s+2\right)}$$

$$U\neq 0\text{ and }s\neq 0\text{ and }s\neq -1\text{ and }s\neq -2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te Us\left(s+1\right)\left(s+2\right), arā, te tauraro pātahi he tino iti rawa te kitea o Us,s\left(s+1\right)\left(s+2\right).

$$\left(s+1\right)\left(s+2\right)Ys=U$$

Whakamahia te āhuatanga tuaritanga hei whakarea te s+1 ki te s+2 ka whakakotahi i ngā kupu rite.

$$\left(s^{2}+3s+2\right)Ys=U$$

Whakamahia te āhuatanga tohatoha hei whakarea te s^{2}+3s+2 ki te Y.

$$\left(s^{2}Y+3sY+2Y\right)s=U$$

Whakamahia te āhuatanga tohatoha hei whakarea te s^{2}Y+3sY+2Y ki te s.

$$Ys^{3}+3Ys^{2}+2Ys=U$$

Pahekotia ngā kīanga tau katoa e whai ana i te Y.

$$\left(s^{3}+3s^{2}+2s\right)Y=U$$

Whakawehea ngā taha e rua ki te 3s^{2}+s^{3}+2s.

$$\frac{\left(s^{3}+3s^{2}+2s\right)Y}{s^{3}+3s^{2}+2s}=\frac{U}{s^{3}+3s^{2}+2s}$$

Mā te whakawehe ki te 3s^{2}+s^{3}+2s ka wetekia te whakareanga ki te 3s^{2}+s^{3}+2s.

$$Y=\frac{U}{s^{3}+3s^{2}+2s}$$

Whakawehe U ki te 3s^{2}+s^{3}+2s.

$$Y=\frac{U}{s\left(s+1\right)\left(s+2\right)}$$

Whakaoti mō U

$$U=Ys\left(s+1\right)\left(s+2\right)$$

$$s\neq 0\text{ and }s\neq -2\text{ and }s\neq -1\text{ and }Y\neq 0$$