Whakaoti i te Y(s)/(x_{s)}=1/s(s+1)(s+2)

$$\frac { Y ( s ) } { ( x _ { s } ) } = \frac { 1 } { s ( s + 1 ) ( s + 2 ) }$$

Whakaoti mō Y

$$Y=\frac{x_{s}}{\left(s+1\right)\left(s+2\right)s^{2}}$$

$$x_{s}\neq 0\text{ and }s\neq 0\text{ and }s\neq -1\text{ and }s\neq -2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te sx_{s}\left(s+1\right)\left(s+2\right), arā, te tauraro pātahi he tino iti rawa te kitea o x_{s},s\left(s+1\right)\left(s+2\right).

$$s\left(s+1\right)\left(s+2\right)Ys=x_{s}$$

Whakamahia te āhuatanga tohatoha hei whakarea te s ki te s+1.

$$\left(s^{2}+s\right)\left(s+2\right)Ys=x_{s}$$

Whakamahia te āhuatanga tuaritanga hei whakarea te s^{2}+s ki te s+2 ka whakakotahi i ngā kupu rite.

$$\left(s^{3}+3s^{2}+2s\right)Ys=x_{s}$$

Whakamahia te āhuatanga tohatoha hei whakarea te s^{3}+3s^{2}+2s ki te Y.

$$\left(s^{3}Y+3s^{2}Y+2sY\right)s=x_{s}$$

Whakamahia te āhuatanga tohatoha hei whakarea te s^{3}Y+3s^{2}Y+2sY ki te s.

$$Ys^{4}+3Ys^{3}+2Ys^{2}=x_{s}$$

Pahekotia ngā kīanga tau katoa e whai ana i te Y.

$$\left(s^{4}+3s^{3}+2s^{2}\right)Y=x_{s}$$

Whakawehea ngā taha e rua ki te s^{4}+3s^{3}+2s^{2}.

$$\frac{\left(s^{4}+3s^{3}+2s^{2}\right)Y}{s^{4}+3s^{3}+2s^{2}}=\frac{x_{s}}{s^{4}+3s^{3}+2s^{2}}$$

Mā te whakawehe ki te s^{4}+3s^{3}+2s^{2} ka wetekia te whakareanga ki te s^{4}+3s^{3}+2s^{2}.

$$Y=\frac{x_{s}}{s^{4}+3s^{3}+2s^{2}}$$

Whakawehe x_{s} ki te s^{4}+3s^{3}+2s^{2}.

$$Y=\frac{x_{s}}{\left(s+1\right)\left(s+2\right)s^{2}}$$