Whakaoti i te P(n2)/C(n+12)=3/2

$$\frac { P ( n 2 ) } { C ( n + 12 ) } = \frac { 3 } { 2 }$$

Whakaoti mō C

$$C=\frac{2Pn_{2}}{3\left(n+12\right)}$$

$$n\neq -12\text{ and }n_{2}\neq 0\text{ and }P\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe C ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te 2C\left(n+12\right), arā, te tauraro pātahi he tino iti rawa te kitea o C\left(n+12\right),2.

$$2Pn_{2}=3C\left(n+12\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 3C ki te n+12.

$$2Pn_{2}=3Cn+36C$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$3Cn+36C=2Pn_{2}$$

Pahekotia ngā kīanga tau katoa e whai ana i te C.

$$\left(3n+36\right)C=2Pn_{2}$$

Whakawehea ngā taha e rua ki te 3n+36.

$$\frac{\left(3n+36\right)C}{3n+36}=\frac{2Pn_{2}}{3n+36}$$

Mā te whakawehe ki te 3n+36 ka wetekia te whakareanga ki te 3n+36.

$$C=\frac{2Pn_{2}}{3n+36}$$

Whakawehe 2Pn_{2} ki te 3n+36.

$$C=\frac{2Pn_{2}}{3\left(n+12\right)}$$

Tē taea kia ōrite te tāupe C ki 0.

$$C=\frac{2Pn_{2}}{3\left(n+12\right)}\text{, }C\neq 0$$

Whakaoti mō P

$$P=\frac{3C\left(n+12\right)}{2n_{2}}$$

$$n_{2}\neq 0\text{ and }C\neq 0\text{ and }n\neq -12$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 2C\left(n+12\right), arā, te tauraro pātahi he tino iti rawa te kitea o C\left(n+12\right),2.

$$2Pn_{2}=3C\left(n+12\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 3C ki te n+12.

$$2Pn_{2}=3Cn+36C$$

He hanga arowhānui tō te whārite.

$$2n_{2}P=3Cn+36C$$

Whakawehea ngā taha e rua ki te 2n_{2}.

$$\frac{2n_{2}P}{2n_{2}}=\frac{3C\left(n+12\right)}{2n_{2}}$$

Mā te whakawehe ki te 2n_{2} ka wetekia te whakareanga ki te 2n_{2}.

$$P=\frac{3C\left(n+12\right)}{2n_{2}}$$