Whakaoti i te A/x^2+B/y^2=9

$$\frac { A } { x ^ { 2 } } + \frac { B } { y ^ { 2 } } = 9$$

Whakaoti mō A

$$A=-\left(\frac{x}{y}\right)^{2}\left(B-9y^{2}\right)$$

$$x\neq 0\text{ and }y\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te x^{2}y^{2}, arā, te tauraro pātahi he tino iti rawa te kitea o x^{2},y^{2}.

$$y^{2}A+x^{2}B=9x^{2}y^{2}$$

Tangohia te x^{2}B mai i ngā taha e rua.

$$y^{2}A=9x^{2}y^{2}-x^{2}B$$

Whakaraupapatia anō ngā kīanga tau.

$$Ay^{2}=9x^{2}y^{2}-Bx^{2}$$

He hanga arowhānui tō te whārite.

$$y^{2}A=9x^{2}y^{2}-Bx^{2}$$

Whakawehea ngā taha e rua ki te y^{2}.

$$\frac{y^{2}A}{y^{2}}=\frac{x^{2}\left(9y^{2}-B\right)}{y^{2}}$$

Mā te whakawehe ki te y^{2} ka wetekia te whakareanga ki te y^{2}.

$$A=\frac{x^{2}\left(9y^{2}-B\right)}{y^{2}}$$

Whakaoti mō B

$$B=-\left(\frac{y}{x}\right)^{2}\left(A-9x^{2}\right)$$

$$x\neq 0\text{ and }y\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te x^{2}y^{2}, arā, te tauraro pātahi he tino iti rawa te kitea o x^{2},y^{2}.

$$y^{2}A+x^{2}B=9x^{2}y^{2}$$

Tangohia te y^{2}A mai i ngā taha e rua.

$$x^{2}B=9x^{2}y^{2}-y^{2}A$$

Whakaraupapatia anō ngā kīanga tau.

$$Bx^{2}=9x^{2}y^{2}-Ay^{2}$$

He hanga arowhānui tō te whārite.

$$x^{2}B=9x^{2}y^{2}-Ay^{2}$$

Whakawehea ngā taha e rua ki te x^{2}.

$$\frac{x^{2}B}{x^{2}}=\frac{y^{2}\left(9x^{2}-A\right)}{x^{2}}$$

Mā te whakawehe ki te x^{2} ka wetekia te whakareanga ki te x^{2}.

$$B=\frac{y^{2}\left(9x^{2}-A\right)}{x^{2}}$$