Whakaoti i te 9/2+5/2y=2y-3

$$\frac { 9 } { 2 } + \frac { 5 } { 2 } y = 2 y - 3$$

Whakaoti mō y

$$y=-15$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 2y mai i ngā taha e rua.

$$\frac{9}{2}+\frac{5}{2}y-2y=-3$$

Pahekotia te \frac{5}{2}y me -2y, ka \frac{1}{2}y.

$$\frac{9}{2}+\frac{1}{2}y=-3$$

Tangohia te \frac{9}{2} mai i ngā taha e rua.

$$\frac{1}{2}y=-3-\frac{9}{2}$$

Me tahuri te -3 ki te hautau -\frac{6}{2}.

$$\frac{1}{2}y=-\frac{6}{2}-\frac{9}{2}$$

Tā te mea he rite te tauraro o -\frac{6}{2} me \frac{9}{2}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{1}{2}y=\frac{-6-9}{2}$$

Tangohia te 9 i te -6, ka -15.

$$\frac{1}{2}y=-\frac{15}{2}$$

Me whakarea ngā taha e rua ki te 2, te tau utu o \frac{1}{2}.

$$y=-\frac{15}{2}\times 2$$

Me whakakore te 2 me te 2.

$$y=-15$$