Whakaoti i te 84+x/94+xgeq9/10

$$\frac { 84 + x } { 94 + x } \geq \frac { 9 } { 10 }$$

Whakaoti mō x

$$x\in (-\infty,-94)\cup [6,\infty)$$

Ngā Upane Otinga

Kāore e taea a te tauraro 94+x te numa kore nā te mea kāore te rituatanga mā te kore e tautuhi. E rua ngā kēhi.

$$94+x>0 94+x<0$$

Whakaarohia te kēhi i ngā wā kei te tōrunga a 94+x. Neke atu a 94 ki te taha matau.

$$x>-94$$

Kāore te tōrite tuatahi e whakarerekē te aronga ina e whakarea ana mā 94+x mō 94+x>0.

$$84+x\geq \frac{9}{10}\left(94+x\right)$$

Whakarea te katoa o te taha matau.

$$84+x\geq \frac{423}{5}+\frac{9}{10}x$$

Neke atu ngā kīanga tau e whai ana i x ki te taha mauī me ētahi atu kupu katoa ki te taha matau.

$$x-\frac{9}{10}x\geq -84+\frac{423}{5}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{1}{10}x\geq \frac{3}{5}$$

Whakawehea ngā taha e rua ki te \frac{1}{10}. I te mea he tōrunga te \frac{1}{10}, kāore e huri te ahunga koreōrite.

$$x\geq 6$$

Tēnā, me whakaarohia te tauira ina e tōraro a 94+x. Neke atu a 94 ki te taha matau.

$$x<-94$$

E whakarerekē ana te aronga o te tōrite tuatahi hei ngā wā e whakarea ana a 94+x mō 94+x<0.

$$84+x\leq \frac{9}{10}\left(94+x\right)$$

Whakarea te katoa o te taha matau.

$$84+x\leq \frac{423}{5}+\frac{9}{10}x$$

Neke atu ngā kīanga tau e whai ana i x ki te taha mauī me ētahi atu kupu katoa ki te taha matau.

$$x-\frac{9}{10}x\leq -84+\frac{423}{5}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{1}{10}x\leq \frac{3}{5}$$

Whakawehea ngā taha e rua ki te \frac{1}{10}. I te mea he tōrunga te \frac{1}{10}, kāore e huri te ahunga koreōrite.

$$x\leq 6$$

Whakaarohia te herenga x<-94 e tautuhi ana ki runga.

$$x<-94$$

Ko te otinga whakamutunga ko te whakakotahi i ngā otinga kua whiwhi.

$$x\in (-\infty,-94)\cup [6,\infty)$$