Whakaoti i te 8x/(x^2-16)-4/(x+4)

$$\frac { 8 x } { ( x ^ { 2 } - 16 ) } - \frac { 4 } { ( x + 4 ) }$$

Aromātai

$$\frac{4}{x-4}$$

Ngā Hipanga Rongoā Poto

Tauwehea te x^{2}-16.

$$\frac{8x}{\left(x-4\right)\left(x+4\right)}-\frac{4}{x+4}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o \left(x-4\right)\left(x+4\right) me x+4 ko \left(x-4\right)\left(x+4\right). Whakareatia \frac{4}{x+4} ki te \frac{x-4}{x-4}.

$$\frac{8x}{\left(x-4\right)\left(x+4\right)}-\frac{4\left(x-4\right)}{\left(x-4\right)\left(x+4\right)}$$

Tā te mea he rite te tauraro o \frac{8x}{\left(x-4\right)\left(x+4\right)} me \frac{4\left(x-4\right)}{\left(x-4\right)\left(x+4\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{8x-4\left(x-4\right)}{\left(x-4\right)\left(x+4\right)}$$

Mahia ngā whakarea i roto o 8x-4\left(x-4\right).

$$\frac{8x-4x+16}{\left(x-4\right)\left(x+4\right)}$$

Whakakotahitia ngā kupu rite i 8x-4x+16.

$$\frac{4x+16}{\left(x-4\right)\left(x+4\right)}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{4x+16}{\left(x-4\right)\left(x+4\right)}.

$$\frac{4\left(x+4\right)}{\left(x-4\right)\left(x+4\right)}$$

Me whakakore tahi te x+4 i te taurunga me te tauraro.

$$\frac{4}{x-4}$$

Tauwehe

$$\frac{4}{x-4}$$