Whakaoti i te 8/x-3x+8y/xy=8y-(3x+8y)/xy=

$$\frac { 8 } { x } - \frac { 3 x + 8 y } { x y } = \frac { 8 y - ( 3 x + 8 y ) } { x y } =$$

Whakaoti mō x

$$x\neq 0$$

$$y\neq 0$$

Ngā Upane Otinga

Tē taea kia ōrite te tāupe x ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te xy, arā, te tauraro pātahi he tino iti rawa te kitea o x,xy.

$$y\times 8-\left(3x+8y\right)=8y-\left(3x+8y\right)$$

Hei kimi i te tauaro o 3x+8y, kimihia te tauaro o ia taurangi.

$$y\times 8-3x-8y=8y-\left(3x+8y\right)$$

Pahekotia te y\times 8 me -8y, ka 0.

$$-3x=8y-\left(3x+8y\right)$$

Hei kimi i te tauaro o 3x+8y, kimihia te tauaro o ia taurangi.

$$-3x=8y-3x-8y$$

Pahekotia te 8y me -8y, ka 0.

$$-3x=-3x$$

Me tāpiri te 3x ki ngā taha e rua.

$$-3x+3x=0$$

Pahekotia te -3x me 3x, ka 0.

$$0=0$$

Whakatauritea te 0 me te 0.

$$\text{true}$$

He pono tēnei mō tētahi x ahakoa.

$$x\in \mathrm{R}$$

Tē taea kia ōrite te tāupe x ki 0.

$$x\in \mathrm{R}\setminus 0$$

Whakaoti mō y

$$y\neq 0$$

$$x\neq 0$$

Ngā Upane Otinga

Tē taea kia ōrite te tāupe y ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te xy, arā, te tauraro pātahi he tino iti rawa te kitea o x,xy.

$$y\times 8-\left(3x+8y\right)=8y-\left(3x+8y\right)$$

Hei kimi i te tauaro o 3x+8y, kimihia te tauaro o ia taurangi.

$$y\times 8-3x-8y=8y-\left(3x+8y\right)$$

Pahekotia te y\times 8 me -8y, ka 0.

$$-3x=8y-\left(3x+8y\right)$$

Hei kimi i te tauaro o 3x+8y, kimihia te tauaro o ia taurangi.

$$-3x=8y-3x-8y$$

Pahekotia te 8y me -8y, ka 0.

$$-3x=-3x$$

Me whakakore te -3 ki ngā taha e rua.

$$x=x$$

Whakaraupapatia anō ngā kīanga tau.

$$\text{true}$$

He pono tēnei mō tētahi y ahakoa.

$$y\in \mathrm{R}$$

Tē taea kia ōrite te tāupe y ki 0.

$$y\in \mathrm{R}\setminus 0$$