Whakaoti i te 7/t-3-t/t+7

$$\frac { 7 } { t - 3 } - \frac { t } { t + 7 }$$

Aromātai

$$\frac{49+10t-t^{2}}{\left(t-3\right)\left(t+7\right)}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o t-3 me t+7 ko \left(t-3\right)\left(t+7\right). Whakareatia \frac{7}{t-3} ki te \frac{t+7}{t+7}. Whakareatia \frac{t}{t+7} ki te \frac{t-3}{t-3}.

$$\frac{7\left(t+7\right)}{\left(t-3\right)\left(t+7\right)}-\frac{t\left(t-3\right)}{\left(t-3\right)\left(t+7\right)}$$

Tā te mea he rite te tauraro o \frac{7\left(t+7\right)}{\left(t-3\right)\left(t+7\right)} me \frac{t\left(t-3\right)}{\left(t-3\right)\left(t+7\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{7\left(t+7\right)-t\left(t-3\right)}{\left(t-3\right)\left(t+7\right)}$$

Mahia ngā whakarea i roto o 7\left(t+7\right)-t\left(t-3\right).

$$\frac{7t+49-t^{2}+3t}{\left(t-3\right)\left(t+7\right)}$$

Whakakotahitia ngā kupu rite i 7t+49-t^{2}+3t.

$$\frac{10t+49-t^{2}}{\left(t-3\right)\left(t+7\right)}$$

Whakarohaina te \left(t-3\right)\left(t+7\right).

$$\frac{10t+49-t^{2}}{t^{2}+4t-21}$$

Kimi Pārōnaki e ai ki t

$$-\frac{14\left(t^{2}+4t+29\right)}{\left(\left(t-3\right)\left(t+7\right)\right)^{2}}$$