Whakaoti i te 7/8x-3/8x=y

$$\frac { 7 } { 8 } x - \frac { 3 } { 8 x } = y$$

Whakaoti mō y

$$y=\frac{7x}{8}-\frac{3}{8x}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 8x, arā, te tauraro pātahi he tino iti rawa te kitea o 8,8x.

$$\frac{7}{8}x\times 8x-3=y\times 8x$$

Whakareatia te \frac{7}{8} ki te 8, ka 7.

$$7xx-3=y\times 8x$$

Whakareatia te x ki te x, ka x^{2}.

$$7x^{2}-3=y\times 8x$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$y\times 8x=7x^{2}-3$$

He hanga arowhānui tō te whārite.

$$8xy=7x^{2}-3$$

Whakawehea ngā taha e rua ki te 8x.

$$\frac{8xy}{8x}=\frac{7x^{2}-3}{8x}$$

Mā te whakawehe ki te 8x ka wetekia te whakareanga ki te 8x.

$$y=\frac{7x^{2}-3}{8x}$$

Whakawehe 7x^{2}-3 ki te 8x.

$$y=\frac{7x}{8}-\frac{3}{8x}$$

Whakaoti mō x

$$x=\frac{\sqrt{16y^{2}+21}+4y}{7}$$

$$x=\frac{-\sqrt{16y^{2}+21}+4y}{7}$$