Whakaoti i te 6x^-4/2x^-3

$$\frac { 6 x ^ { - 4 } } { 2 x ^ { - 3 } }$$

Aromātai

$$\frac{3}{x}$$

Ngā Upane mō te Hua o ngā Pānga Taupū e Rua

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\left(6x^{-4}\right)^{1}\times \frac{1}{2x^{-3}}$$

Hei hiki i te hua o ngā tau e rua, neke atu rānei ki tētahi pū, hīkina ia tau ki te pū ka tuhi ko tāna hua.

$$6^{1}\left(x^{-4}\right)^{1}\times \frac{1}{2}\times \frac{1}{x^{-3}}$$

Whakamahia te Āhuatanga Kōaro o te Whakareanga.

$$6^{1}\times \frac{1}{2}\left(x^{-4}\right)^{1}\times \frac{1}{x^{-3}}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū.

$$6^{1}\times \frac{1}{2}x^{-4}x^{-3\left(-1\right)}$$

Whakareatia -3 ki te -1.

$$6^{1}\times \frac{1}{2}x^{-4}x^{3}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$6^{1}\times \frac{1}{2}x^{-4+3}$$

Tāpirihia ngā taupū -4 me 3.

$$6^{1}\times \frac{1}{2}\times \frac{1}{x}$$

Hīkina te 6 ki te pū 1.

$$6\times \frac{1}{2}\times \frac{1}{x}$$

Whakareatia 6 ki te \frac{1}{2}.

$$3\times \frac{1}{x}$$

Kimi Pārōnaki e ai ki x

$$-\frac{3}{x^{2}}$$

Ngā Upane Otinga

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{6}{2}x^{-4-\left(-3\right)})$$

Mahia ngā tātaitanga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3\times \frac{1}{x})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$-3x^{-1-1}$$

Mahia ngā tātaitanga.

$$-3x^{-2}$$