Whakaoti i te frac{50*a^{3}*(-b^{5})^3}{5^2*(a*b^6)^2}=

$$\frac { 50 \cdot a ^ { 3 } \cdot ( - b ^ { 5 } ) ^ { 3 } } { 5 ^ { 2 } \cdot ( a \cdot b ^ { 6 } ) ^ { 2 } } =$$

Aromātai

$$-2ab^{3}$$

Ngā Hipanga Rongoā Poto

Tātaihia te 5 mā te pū o 2, kia riro ko 25.

$$\frac{50a^{3}\left(-b^{5}\right)^{3}}{25\left(ab^{6}\right)^{2}}$$

Whakarohaina te \left(ab^{6}\right)^{2}.

$$\frac{50a^{3}\left(-b^{5}\right)^{3}}{25a^{2}\left(b^{6}\right)^{2}}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 6 me te 2 kia riro ai te 12.

$$\frac{50a^{3}\left(-b^{5}\right)^{3}}{25a^{2}b^{12}}$$

Me whakakore tahi te 25a^{2} i te taurunga me te tauraro.

$$\frac{2a\left(-b^{5}\right)^{3}}{b^{12}}$$

Whakarohaina te \left(-b^{5}\right)^{3}.

$$\frac{2a\left(-1\right)^{3}\left(b^{5}\right)^{3}}{b^{12}}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 5 me te 3 kia riro ai te 15.

$$\frac{2a\left(-1\right)^{3}b^{15}}{b^{12}}$$

Tātaihia te -1 mā te pū o 3, kia riro ko -1.

$$\frac{2a\left(-1\right)b^{15}}{b^{12}}$$

Whakareatia te 2 ki te -1, ka -2.

$$\frac{-2ab^{15}}{b^{12}}$$

Me whakakore tahi te b^{12} i te taurunga me te tauraro.

$$-2ab^{3}$$

Whakaroha

$$-2ab^{3}$$

Ngā Hipanga Rongoā Poto

Tātaihia te 5 mā te pū o 2, kia riro ko 25.

$$\frac{50a^{3}\left(-b^{5}\right)^{3}}{25\left(ab^{6}\right)^{2}}$$

Whakarohaina te \left(ab^{6}\right)^{2}.

$$\frac{50a^{3}\left(-b^{5}\right)^{3}}{25a^{2}\left(b^{6}\right)^{2}}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 6 me te 2 kia riro ai te 12.

$$\frac{50a^{3}\left(-b^{5}\right)^{3}}{25a^{2}b^{12}}$$

Me whakakore tahi te 25a^{2} i te taurunga me te tauraro.

$$\frac{2a\left(-b^{5}\right)^{3}}{b^{12}}$$

Whakarohaina te \left(-b^{5}\right)^{3}.

$$\frac{2a\left(-1\right)^{3}\left(b^{5}\right)^{3}}{b^{12}}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 5 me te 3 kia riro ai te 15.

$$\frac{2a\left(-1\right)^{3}b^{15}}{b^{12}}$$

Tātaihia te -1 mā te pū o 3, kia riro ko -1.

$$\frac{2a\left(-1\right)b^{15}}{b^{12}}$$

Whakareatia te 2 ki te -1, ka -2.

$$\frac{-2ab^{15}}{b^{12}}$$

Me whakakore tahi te b^{12} i te taurunga me te tauraro.

$$-2ab^{3}$$