Whakaoti i te 5a-1/6-3a-1/4=1/12*(a+1)

$$\frac { 5 a - 1 } { 6 } - \frac { 3 a - 1 } { 4 } = \frac { 1 } { 12 } \cdot ( a + 1 )$$

Whakaoti mō a (complex solution)

$$a\in \mathrm{C}$$

Ngā Upane Otinga

Me whakarea ngā taha e rua o te whārite ki te 12, arā, te tauraro pātahi he tino iti rawa te kitea o 6,4,12.

$$2\left(5a-1\right)-3\left(3a-1\right)=1\left(a+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te 5a-1.

$$10a-2-3\left(3a-1\right)=1\left(a+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te 3a-1.

$$10a-2-9a+3=1\left(a+1\right)$$

Pahekotia te 10a me -9a, ka a.

$$a-2+3=1\left(a+1\right)$$

Tāpirihia te -2 ki te 3, ka 1.

$$a+1=1\left(a+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 1 ki te a+1.

$$a+1=a+1$$

Tangohia te a mai i ngā taha e rua.

$$a+1-a=1$$

Pahekotia te a me -a, ka 0.

$$1=1$$

Whakatauritea te 1 me te 1.

$$\text{true}$$

He pono tēnei mō tētahi a ahakoa.

$$a\in \mathrm{C}$$

Whakaoti mō a

$$a\in \mathrm{R}$$

Ngā Upane Otinga

Me whakarea ngā taha e rua o te whārite ki te 12, arā, te tauraro pātahi he tino iti rawa te kitea o 6,4,12.

$$2\left(5a-1\right)-3\left(3a-1\right)=1\left(a+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te 5a-1.

$$10a-2-3\left(3a-1\right)=1\left(a+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te 3a-1.

$$10a-2-9a+3=1\left(a+1\right)$$

Pahekotia te 10a me -9a, ka a.

$$a-2+3=1\left(a+1\right)$$

Tāpirihia te -2 ki te 3, ka 1.

$$a+1=1\left(a+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 1 ki te a+1.

$$a+1=a+1$$

Tangohia te a mai i ngā taha e rua.

$$a+1-a=1$$

Pahekotia te a me -a, ka 0.

$$1=1$$

Whakatauritea te 1 me te 1.

$$\text{true}$$

He pono tēnei mō tētahi a ahakoa.

$$a\in \mathrm{R}$$