Whakaoti i te 5/x+3+3

$$\frac { 5 } { x + 3 } + 3$$

Aromātai

$$\frac{3x+14}{x+3}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 3 ki te \frac{x+3}{x+3}.

$$\frac{5}{x+3}+\frac{3\left(x+3\right)}{x+3}$$

Tā te mea he rite te tauraro o \frac{5}{x+3} me \frac{3\left(x+3\right)}{x+3}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{5+3\left(x+3\right)}{x+3}$$

Mahia ngā whakarea i roto o 5+3\left(x+3\right).

$$\frac{5+3x+9}{x+3}$$

Whakakotahitia ngā kupu rite i 5+3x+9.

$$\frac{14+3x}{x+3}$$

Kimi Pārōnaki e ai ki x

$$-\frac{5}{\left(x+3\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 3 ki te \frac{x+3}{x+3}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{5}{x+3}+\frac{3\left(x+3\right)}{x+3})$$

Tā te mea he rite te tauraro o \frac{5}{x+3} me \frac{3\left(x+3\right)}{x+3}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{5+3\left(x+3\right)}{x+3})$$

Mahia ngā whakarea i roto o 5+3\left(x+3\right).

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{5+3x+9}{x+3})$$

Whakakotahitia ngā kupu rite i 5+3x+9.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{14+3x}{x+3})$$

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(x^{1}+3\right)\frac{\mathrm{d}}{\mathrm{d}x}(3x^{1}+14)-\left(3x^{1}+14\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{1}+3)}{\left(x^{1}+3\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(x^{1}+3\right)\times 3x^{1-1}-\left(3x^{1}+14\right)x^{1-1}}{\left(x^{1}+3\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{\left(x^{1}+3\right)\times 3x^{0}-\left(3x^{1}+14\right)x^{0}}{\left(x^{1}+3\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{x^{1}\times 3x^{0}+3\times 3x^{0}-\left(3x^{1}x^{0}+14x^{0}\right)}{\left(x^{1}+3\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{3x^{1}+3\times 3x^{0}-\left(3x^{1}+14x^{0}\right)}{\left(x^{1}+3\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{3x^{1}+9x^{0}-\left(3x^{1}+14x^{0}\right)}{\left(x^{1}+3\right)^{2}}$$

Tangohia ngā taiapa kāore i te hiahiatia.

$$\frac{3x^{1}+9x^{0}-3x^{1}-14x^{0}}{\left(x^{1}+3\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(3-3\right)x^{1}+\left(9-14\right)x^{0}}{\left(x^{1}+3\right)^{2}}$$

Tangohia te 3 i 3 me te 14 i te 9.

$$\frac{-5x^{0}}{\left(x^{1}+3\right)^{2}}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{-5x^{0}}{\left(x+3\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{-5}{\left(x+3\right)^{2}}$$