Whakaoti i te 5/9-x*1/3=2/3

$$\frac { 5 } { 9 } - x \cdot \frac { 1 } { 3 } = \frac { 2 } { 3 }$$

Whakaoti mō x

$$x=-\frac{1}{3}\approx -0.333333333$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te -1 ki te \frac{1}{3}, ka -\frac{1}{3}.

$$\frac{5}{9}-\frac{1}{3}x=\frac{2}{3}$$

Tangohia te \frac{5}{9} mai i ngā taha e rua.

$$-\frac{1}{3}x=\frac{2}{3}-\frac{5}{9}$$

Ko te maha noa iti rawa atu o 3 me 9 ko 9. Me tahuri \frac{2}{3} me \frac{5}{9} ki te hautau me te tautūnga 9.

$$-\frac{1}{3}x=\frac{6}{9}-\frac{5}{9}$$

Tā te mea he rite te tauraro o \frac{6}{9} me \frac{5}{9}, me tango rāua mā te tango i ō raua taurunga.

$$-\frac{1}{3}x=\frac{6-5}{9}$$

Tangohia te 5 i te 6, ka 1.

$$-\frac{1}{3}x=\frac{1}{9}$$

Me whakarea ngā taha e rua ki te -3, te tau utu o -\frac{1}{3}.

$$x=\frac{1}{9}\left(-3\right)$$

Whakareatia te \frac{1}{9} ki te -3, ka \frac{-3}{9}.

$$x=\frac{-3}{9}$$

Whakahekea te hautanga \frac{-3}{9} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$x=-\frac{1}{3}$$