Whakaoti i te 5/9(F-32)=C

$$\frac { 5 } { 9 } ( F - 32 ) = C$$

Whakaoti mō C

$$C=\frac{5\left(F-32\right)}{9}$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{5}{9} ki te F-32.

$$\frac{5}{9}F-\frac{160}{9}=C$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$C=\frac{5}{9}F-\frac{160}{9}$$

Whakaoti mō F

$$F=\frac{9C}{5}+32$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{5}{9} ki te F-32.

$$\frac{5}{9}F-\frac{160}{9}=C$$

Me tāpiri te \frac{160}{9} ki ngā taha e rua.

$$\frac{5}{9}F=C+\frac{160}{9}$$

Whakawehea ngā taha e rua o te whārite ki te \frac{5}{9}, he ōrite ki te whakarea i ngā taha e rua ki te tau huripoki o te hautanga.

$$\frac{\frac{5}{9}F}{\frac{5}{9}}=\frac{C+\frac{160}{9}}{\frac{5}{9}}$$

Mā te whakawehe ki te \frac{5}{9} ka wetekia te whakareanga ki te \frac{5}{9}.

$$F=\frac{C+\frac{160}{9}}{\frac{5}{9}}$$

Whakawehe C+\frac{160}{9} ki te \frac{5}{9} mā te whakarea C+\frac{160}{9} ki te tau huripoki o \frac{5}{9}.

$$F=\frac{9C}{5}+32$$