Whakaoti i te 5/4x+1/2=1/4(4x-1)

$$\frac { 5 } { 4 } x + \frac { 1 } { 2 } = \frac { 1 } { 4 } ( 4 x - 1 )$$

Whakaoti mō x

$$x=-3$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{4} ki te 4x-1.

$$\frac{5}{4}x+\frac{1}{2}=\frac{1}{4}\times 4x+\frac{1}{4}\left(-1\right)$$

Me whakakore te 4 me te 4.

$$\frac{5}{4}x+\frac{1}{2}=x+\frac{1}{4}\left(-1\right)$$

Whakareatia te \frac{1}{4} ki te -1, ka -\frac{1}{4}.

$$\frac{5}{4}x+\frac{1}{2}=x-\frac{1}{4}$$

Tangohia te x mai i ngā taha e rua.

$$\frac{5}{4}x+\frac{1}{2}-x=-\frac{1}{4}$$

Pahekotia te \frac{5}{4}x me -x, ka \frac{1}{4}x.

$$\frac{1}{4}x+\frac{1}{2}=-\frac{1}{4}$$

Tangohia te \frac{1}{2} mai i ngā taha e rua.

$$\frac{1}{4}x=-\frac{1}{4}-\frac{1}{2}$$

Ko te maha noa iti rawa atu o 4 me 2 ko 4. Me tahuri -\frac{1}{4} me \frac{1}{2} ki te hautau me te tautūnga 4.

$$\frac{1}{4}x=-\frac{1}{4}-\frac{2}{4}$$

Tā te mea he rite te tauraro o -\frac{1}{4} me \frac{2}{4}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{1}{4}x=\frac{-1-2}{4}$$

Tangohia te 2 i te -1, ka -3.

$$\frac{1}{4}x=-\frac{3}{4}$$

Me whakarea ngā taha e rua ki te 4, te tau utu o \frac{1}{4}.

$$x=-\frac{3}{4}\times 4$$

Me whakakore te 4 me te 4.

$$x=-3$$