Whakaoti i te 5/2-i+ki

$$\frac { 5 } { 2 - i } + k i$$

Aromātai

$$ik+\left(2+i\right)$$

Ngā Upane Otinga

Me whakarea te taurunga me te tauraro o \frac{5}{2-i} ki te haumi hiato o te tauraro, 2+i.

$$\frac{5\left(2+i\right)}{\left(2-i\right)\left(2+i\right)}+ki$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{5\left(2+i\right)}{2^{2}-i^{2}}+ki$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$\frac{5\left(2+i\right)}{5}+ki$$

Whakareatia 5 ki te 2+i.

$$\frac{5\times 2+5i}{5}+ki$$

Mahia ngā whakarea i roto o 5\times 2+5i.

$$\frac{10+5i}{5}+ki$$

Whakawehea te 10+5i ki te 5, kia riro ko 2+i.

$$2+i+ki$$