Whakaoti i te 5+3i/2-4i=

$$\frac { 5 + 3 i } { 2 - 4 i } =$$

Aromātai

$$-\frac{1}{10}+\frac{13}{10}i=-0.1+1.3i$$

Ngā Upane Otinga

Whakareatia te taurunga me te tauraro ki te haumi hiato o te tauraro, 2+4i.

$$\frac{\left(5+3i\right)\left(2+4i\right)}{\left(2-4i\right)\left(2+4i\right)}$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{\left(5+3i\right)\left(2+4i\right)}{2^{2}-4^{2}i^{2}}$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$\frac{\left(5+3i\right)\left(2+4i\right)}{20}$$

Me whakarea ngā tau matatini 5+3i me 2+4i pēnā i te whakarea huarua.

$$\frac{5\times 2+5\times \left(4i\right)+3i\times 2+3\times 4i^{2}}{20}$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$\frac{5\times 2+5\times \left(4i\right)+3i\times 2+3\times 4\left(-1\right)}{20}$$

Mahia ngā whakarea i roto o 5\times 2+5\times \left(4i\right)+3i\times 2+3\times 4\left(-1\right).

$$\frac{10+20i+6i-12}{20}$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 10+20i+6i-12.

$$\frac{10-12+\left(20+6\right)i}{20}$$

Mahia ngā tāpiri i roto o 10-12+\left(20+6\right)i.

$$\frac{-2+26i}{20}$$

Whakawehea te -2+26i ki te 20, kia riro ko -\frac{1}{10}+\frac{13}{10}i.

$$-\frac{1}{10}+\frac{13}{10}i$$

Wāhi Tūturu

$$-\frac{1}{10} = -0.1$$

Ngā Upane Otinga

Me whakarea te taurunga me te tauraro o \frac{5+3i}{2-4i} ki te haumi hiato o te tauraro, 2+4i.

$$Re(\frac{\left(5+3i\right)\left(2+4i\right)}{\left(2-4i\right)\left(2+4i\right)})$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$Re(\frac{\left(5+3i\right)\left(2+4i\right)}{2^{2}-4^{2}i^{2}})$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$Re(\frac{\left(5+3i\right)\left(2+4i\right)}{20})$$

Me whakarea ngā tau matatini 5+3i me 2+4i pēnā i te whakarea huarua.

$$Re(\frac{5\times 2+5\times \left(4i\right)+3i\times 2+3\times 4i^{2}}{20})$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$Re(\frac{5\times 2+5\times \left(4i\right)+3i\times 2+3\times 4\left(-1\right)}{20})$$

Mahia ngā whakarea i roto o 5\times 2+5\times \left(4i\right)+3i\times 2+3\times 4\left(-1\right).

$$Re(\frac{10+20i+6i-12}{20})$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 10+20i+6i-12.

$$Re(\frac{10-12+\left(20+6\right)i}{20})$$

Mahia ngā tāpiri i roto o 10-12+\left(20+6\right)i.

$$Re(\frac{-2+26i}{20})$$

Whakawehea te -2+26i ki te 20, kia riro ko -\frac{1}{10}+\frac{13}{10}i.

$$Re(-\frac{1}{10}+\frac{13}{10}i)$$

Ko te wāhi tūturu o -\frac{1}{10}+\frac{13}{10}i ko -\frac{1}{10}.

$$-\frac{1}{10}$$