Whakaoti i te 40xy^5/16x^2y^3

$$\frac { 40 x y ^ { 5 } } { 16 x ^ { 2 } y ^ { 3 } }$$

Aromātai

$$\frac{5y^{2}}{2x}$$

Ngā Upane e Whakamahi ana i te Āhuatanga o te Otinga o ngā Pū

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\frac{40^{1}x^{1}y^{5}}{16^{1}x^{2}y^{3}}$$

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{40^{1}}{16^{1}}x^{1-2}y^{5-3}$$

Tango 2 mai i 1.

$$\frac{40^{1}}{16^{1}}\times \frac{1}{x}y^{5-3}$$

Tango 3 mai i 5.

$$\frac{40^{1}}{16^{1}}\times \frac{1}{x}y^{2}$$

Whakahekea te hautanga \frac{40}{16} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 8.

$$\frac{5}{2}\times \frac{1}{x}y^{2}$$

Kimi Pārōnaki e ai ki x

$$-\frac{5\times \left(\frac{y}{x}\right)^{2}}{2}$$

Ngā Upane Otinga

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{40y^{5}}{16y^{3}}x^{1-2})$$

Mahia ngā tātaitanga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{5y^{2}}{2}\times \frac{1}{x})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$-\frac{5y^{2}}{2}x^{-1-1}$$

Mahia ngā tātaitanga.

$$\left(-\frac{5y^{2}}{2}\right)x^{-2}$$