Whakaoti i te 4x/3x^2+x

$$\frac { 4 x } { 3 x ^ { 2 } + x }$$

Aromātai

$$\frac{4}{3x+1}$$

Ngā Hipanga Rongoā Poto

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{4x}{x\left(3x+1\right)}$$

Me whakakore tahi te x i te taurunga me te tauraro.

$$\frac{4}{3x+1}$$

Kimi Pārōnaki e ai ki x

$$-\frac{12}{\left(3x+1\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(3x^{2}+x^{1}\right)\frac{\mathrm{d}}{\mathrm{d}x}(4x^{1})-4x^{1}\frac{\mathrm{d}}{\mathrm{d}x}(3x^{2}+x^{1})}{\left(3x^{2}+x^{1}\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(3x^{2}+x^{1}\right)\times 4x^{1-1}-4x^{1}\left(2\times 3x^{2-1}+x^{1-1}\right)}{\left(3x^{2}+x^{1}\right)^{2}}$$

Whakarūnātia.

$$\frac{\left(3x^{2}+x^{1}\right)\times 4x^{0}-4x^{1}\left(6x^{1}+x^{0}\right)}{\left(3x^{2}+x^{1}\right)^{2}}$$

Whakareatia 3x^{2}+x^{1} ki te 4x^{0}.

$$\frac{3x^{2}\times 4x^{0}+x^{1}\times 4x^{0}-4x^{1}\left(6x^{1}+x^{0}\right)}{\left(3x^{2}+x^{1}\right)^{2}}$$

Whakareatia 4x^{1} ki te 6x^{1}+x^{0}.

$$\frac{3x^{2}\times 4x^{0}+x^{1}\times 4x^{0}-\left(4x^{1}\times 6x^{1}+4x^{1}x^{0}\right)}{\left(3x^{2}+x^{1}\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{3\times 4x^{2}+4x^{1}-\left(4\times 6x^{1+1}+4x^{1}\right)}{\left(3x^{2}+x^{1}\right)^{2}}$$

Whakarūnātia.

$$\frac{12x^{2}+4x^{1}-\left(24x^{2}+4x^{1}\right)}{\left(3x^{2}+x^{1}\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{-12x^{2}}{\left(3x^{2}+x^{1}\right)^{2}}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{-12x^{2}}{\left(3x^{2}+x\right)^{2}}$$