Whakaoti i te 4s/(25s^2-9t^2)-s/(5s-3t)

$$\frac { 4 s } { ( 25 s ^ { 2 } - 9 t ^ { 2 } ) } - \frac { s } { ( 5 s - 3 t ) }$$

Aromātai

$$\frac{s\left(4-3t-5s\right)}{25s^{2}-9t^{2}}$$

Ngā Hipanga Rongoā Poto

Tauwehea te 25s^{2}-9t^{2}.

$$\frac{4s}{\left(5s-3t\right)\left(5s+3t\right)}-\frac{s}{5s-3t}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o \left(5s-3t\right)\left(5s+3t\right) me 5s-3t ko \left(5s-3t\right)\left(5s+3t\right). Whakareatia \frac{s}{5s-3t} ki te \frac{5s+3t}{5s+3t}.

$$\frac{4s}{\left(5s-3t\right)\left(5s+3t\right)}-\frac{s\left(5s+3t\right)}{\left(5s-3t\right)\left(5s+3t\right)}$$

Tā te mea he rite te tauraro o \frac{4s}{\left(5s-3t\right)\left(5s+3t\right)} me \frac{s\left(5s+3t\right)}{\left(5s-3t\right)\left(5s+3t\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{4s-s\left(5s+3t\right)}{\left(5s-3t\right)\left(5s+3t\right)}$$

Mahia ngā whakarea i roto o 4s-s\left(5s+3t\right).

$$\frac{4s-5s^{2}-3st}{\left(5s-3t\right)\left(5s+3t\right)}$$

Whakarohaina te \left(5s-3t\right)\left(5s+3t\right).

$$\frac{4s-5s^{2}-3st}{25s^{2}-9t^{2}}$$

Tauwehe

$$\frac{s\left(4-3t-5s\right)}{25s^{2}-9t^{2}}$$