Whakaoti i te 4-5i/2-i

$$\frac { 4 - 5 i } { 2 - i }$$

Aromātai

$$\frac{13}{5}-\frac{6}{5}i=2.6-1.2i$$

Ngā Upane Otinga

Whakareatia te taurunga me te tauraro ki te haumi hiato o te tauraro, 2+i.

$$\frac{\left(4-5i\right)\left(2+i\right)}{\left(2-i\right)\left(2+i\right)}$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{\left(4-5i\right)\left(2+i\right)}{2^{2}-i^{2}}$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$\frac{\left(4-5i\right)\left(2+i\right)}{5}$$

Me whakarea ngā tau matatini 4-5i me 2+i pēnā i te whakarea huarua.

$$\frac{4\times 2+4i-5i\times 2-5i^{2}}{5}$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$\frac{4\times 2+4i-5i\times 2-5\left(-1\right)}{5}$$

Mahia ngā whakarea i roto o 4\times 2+4i-5i\times 2-5\left(-1\right).

$$\frac{8+4i-10i+5}{5}$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 8+4i-10i+5.

$$\frac{8+5+\left(4-10\right)i}{5}$$

Mahia ngā tāpiri i roto o 8+5+\left(4-10\right)i.

$$\frac{13-6i}{5}$$

Whakawehea te 13-6i ki te 5, kia riro ko \frac{13}{5}-\frac{6}{5}i.

$$\frac{13}{5}-\frac{6}{5}i$$

Wāhi Tūturu

$$\frac{13}{5} = 2\frac{3}{5} = 2.6$$

Ngā Upane Otinga

Me whakarea te taurunga me te tauraro o \frac{4-5i}{2-i} ki te haumi hiato o te tauraro, 2+i.

$$Re(\frac{\left(4-5i\right)\left(2+i\right)}{\left(2-i\right)\left(2+i\right)})$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$Re(\frac{\left(4-5i\right)\left(2+i\right)}{2^{2}-i^{2}})$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$Re(\frac{\left(4-5i\right)\left(2+i\right)}{5})$$

Me whakarea ngā tau matatini 4-5i me 2+i pēnā i te whakarea huarua.

$$Re(\frac{4\times 2+4i-5i\times 2-5i^{2}}{5})$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$Re(\frac{4\times 2+4i-5i\times 2-5\left(-1\right)}{5})$$

Mahia ngā whakarea i roto o 4\times 2+4i-5i\times 2-5\left(-1\right).

$$Re(\frac{8+4i-10i+5}{5})$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 8+4i-10i+5.

$$Re(\frac{8+5+\left(4-10\right)i}{5})$$

Mahia ngā tāpiri i roto o 8+5+\left(4-10\right)i.

$$Re(\frac{13-6i}{5})$$

Whakawehea te 13-6i ki te 5, kia riro ko \frac{13}{5}-\frac{6}{5}i.

$$Re(\frac{13}{5}-\frac{6}{5}i)$$

Ko te wāhi tūturu o \frac{13}{5}-\frac{6}{5}i ko \frac{13}{5}.

$$\frac{13}{5}$$