Whakaoti i te 4(x+2)/3-6(x-7)/7geq12

$$\frac { 4 ( x + 2 ) } { 3 } - \frac { 6 ( x - 7 ) } { 7 } \geq 12$$

Whakaoti mō x

$$x\geq 7$$

Ngā Upane Otinga

Me whakarea ngā taha e rua o te whārite ki te 21, arā, te tauraro pātahi he tino iti rawa te kitea o 3,7. I te mea he tōrunga te 21, kāore e huri te ahunga koreōrite.

$$7\times 4\left(x+2\right)-3\times 6\left(x-7\right)\geq 252$$

Whakareatia te 7 ki te 4, ka 28.

$$28\left(x+2\right)-3\times 6\left(x-7\right)\geq 252$$

Whakamahia te āhuatanga tohatoha hei whakarea te 28 ki te x+2.

$$28x+56-3\times 6\left(x-7\right)\geq 252$$

Whakareatia te -3 ki te 6, ka -18.

$$28x+56-18\left(x-7\right)\geq 252$$

Whakamahia te āhuatanga tohatoha hei whakarea te -18 ki te x-7.

$$28x+56-18x+126\geq 252$$

Pahekotia te 28x me -18x, ka 10x.

$$10x+56+126\geq 252$$

Tāpirihia te 56 ki te 126, ka 182.

$$10x+182\geq 252$$

Tangohia te 182 mai i ngā taha e rua.

$$10x\geq 252-182$$

Tangohia te 182 i te 252, ka 70.

$$10x\geq 70$$

Whakawehea ngā taha e rua ki te 10. I te mea he tōrunga te 10, kāore e huri te ahunga koreōrite.

$$x\geq \frac{70}{10}$$

Whakawehea te 70 ki te 10, kia riro ko 7.

$$x\geq 7$$