Whakaoti i te 4/3x+1/2-5/3x=1/4-1-frac{3}{4}x

$$\frac { 4 } { 3 } x + \frac { 1 } { 2 } - \frac { 5 } { 3 } x = \frac { 1 } { 4 } - 1 - \frac { 3 } { 4 } x$$

Whakaoti mō x

$$x=-3$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Pahekotia te \frac{4}{3}x me -\frac{5}{3}x, ka -\frac{1}{3}x.

$$-\frac{1}{3}x+\frac{1}{2}=\frac{1}{4}-1-\frac{3}{4}x$$

Me tahuri te 1 ki te hautau \frac{4}{4}.

$$-\frac{1}{3}x+\frac{1}{2}=\frac{1}{4}-\frac{4}{4}-\frac{3}{4}x$$

Tā te mea he rite te tauraro o \frac{1}{4} me \frac{4}{4}, me tango rāua mā te tango i ō raua taurunga.

$$-\frac{1}{3}x+\frac{1}{2}=\frac{1-4}{4}-\frac{3}{4}x$$

Tangohia te 4 i te 1, ka -3.

$$-\frac{1}{3}x+\frac{1}{2}=-\frac{3}{4}-\frac{3}{4}x$$

Me tāpiri te \frac{3}{4}x ki ngā taha e rua.

$$-\frac{1}{3}x+\frac{1}{2}+\frac{3}{4}x=-\frac{3}{4}$$

Pahekotia te -\frac{1}{3}x me \frac{3}{4}x, ka \frac{5}{12}x.

$$\frac{5}{12}x+\frac{1}{2}=-\frac{3}{4}$$

Tangohia te \frac{1}{2} mai i ngā taha e rua.

$$\frac{5}{12}x=-\frac{3}{4}-\frac{1}{2}$$

Ko te maha noa iti rawa atu o 4 me 2 ko 4. Me tahuri -\frac{3}{4} me \frac{1}{2} ki te hautau me te tautūnga 4.

$$\frac{5}{12}x=-\frac{3}{4}-\frac{2}{4}$$

Tā te mea he rite te tauraro o -\frac{3}{4} me \frac{2}{4}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{5}{12}x=\frac{-3-2}{4}$$

Tangohia te 2 i te -3, ka -5.

$$\frac{5}{12}x=-\frac{5}{4}$$

Me whakarea ngā taha e rua ki te \frac{12}{5}, te tau utu o \frac{5}{12}.

$$x=-\frac{5}{4}\times \frac{12}{5}$$

Me whakarea te -\frac{5}{4} ki te \frac{12}{5} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$x=\frac{-5\times 12}{4\times 5}$$

Mahia ngā whakarea i roto i te hautanga \frac{-5\times 12}{4\times 5}.

$$x=\frac{-60}{20}$$

Whakawehea te -60 ki te 20, kia riro ko -3.

$$x=-3$$