Whakaoti i te 4/3(x-2)=4-3

$$\frac { 4 } { 3 } ( x - 2 ) = 4 - 3$$

Whakaoti mō x

$$x = \frac{11}{4} = 2\frac{3}{4} = 2.75$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{4}{3} ki te x-2.

$$\frac{4}{3}x+\frac{4}{3}\left(-2\right)=4-3$$

Tuhia te \frac{4}{3}\left(-2\right) hei hautanga kotahi.

$$\frac{4}{3}x+\frac{4\left(-2\right)}{3}=4-3$$

Whakareatia te 4 ki te -2, ka -8.

$$\frac{4}{3}x+\frac{-8}{3}=4-3$$

Ka taea te hautanga \frac{-8}{3} te tuhi anō ko -\frac{8}{3} mā te tango i te tohu tōraro.

$$\frac{4}{3}x-\frac{8}{3}=4-3$$

Tangohia te 3 i te 4, ka 1.

$$\frac{4}{3}x-\frac{8}{3}=1$$

Me tāpiri te \frac{8}{3} ki ngā taha e rua.

$$\frac{4}{3}x=1+\frac{8}{3}$$

Me tahuri te 1 ki te hautau \frac{3}{3}.

$$\frac{4}{3}x=\frac{3}{3}+\frac{8}{3}$$

Tā te mea he rite te tauraro o \frac{3}{3} me \frac{8}{3}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{4}{3}x=\frac{3+8}{3}$$

Tāpirihia te 3 ki te 8, ka 11.

$$\frac{4}{3}x=\frac{11}{3}$$

Me whakarea ngā taha e rua ki te \frac{3}{4}, te tau utu o \frac{4}{3}.

$$x=\frac{11}{3}\times \frac{3}{4}$$

Me whakarea te \frac{11}{3} ki te \frac{3}{4} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$x=\frac{11\times 3}{3\times 4}$$

Me whakakore tahi te 3 i te taurunga me te tauraro.

$$x=\frac{11}{4}$$