Whakaoti i te 3y^2/2-6=0

$$\frac { 3 y ^ { 2 } } { 2 } - 6 = 0$$

Whakaoti mō y

$$y=2$$

$$y=-2$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Whakareatia ngā taha e rua o te whārite ki te 2.

$$3y^{2}-12=0$$

Whakawehea ngā taha e rua ki te 3.

$$y^{2}-4=0$$

Whakaarohia te y^{2}-4. Tuhia anō te y^{2}-4 hei y^{2}-2^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(y-2\right)\left(y+2\right)=0$$

Hei kimi otinga whārite, me whakaoti te y-2=0 me te y+2=0.

$$y=2 y=-2$$

Ngā Upane mā te Kimi Pūtakerua

Whakareatia ngā taha e rua o te whārite ki te 2.

$$3y^{2}-12=0$$

Me tāpiri te 12 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$3y^{2}=12$$

Whakawehea ngā taha e rua ki te 3.

$$y^{2}=\frac{12}{3}$$

Whakawehea te 12 ki te 3, kia riro ko 4.

$$y^{2}=4$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$y=2 y=-2$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakareatia ngā taha e rua o te whārite ki te 2.

$$3y^{2}-12=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 3 mō a, 0 mō b, me -12 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$y=\frac{0±\sqrt{0^{2}-4\times 3\left(-12\right)}}{2\times 3}$$

Pūrua 0.

$$y=\frac{0±\sqrt{-4\times 3\left(-12\right)}}{2\times 3}$$

Whakareatia -4 ki te 3.

$$y=\frac{0±\sqrt{-12\left(-12\right)}}{2\times 3}$$

Whakareatia -12 ki te -12.

$$y=\frac{0±\sqrt{144}}{2\times 3}$$

Tuhia te pūtakerua o te 144.

$$y=\frac{0±12}{2\times 3}$$

Whakareatia 2 ki te 3.

$$y=\frac{0±12}{6}$$

Nā, me whakaoti te whārite y=\frac{0±12}{6} ina he tāpiri te ±. Whakawehe 12 ki te 6.

$$y=2$$

Nā, me whakaoti te whārite y=\frac{0±12}{6} ina he tango te ±. Whakawehe -12 ki te 6.

$$y=-2$$

Kua oti te whārite te whakatau.

$$y=2 y=-2$$