Whakaoti i te 3x/x-4+5/(x-4)^2

$$\frac { 3 x } { x - 4 } + \frac { 5 } { ( x - 4 ) ^ { 2 } }$$

Aromātai

$$\frac{3x^{2}-12x+5}{\left(x-4\right)^{2}}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x-4 me \left(x-4\right)^{2} ko \left(x-4\right)^{2}. Whakareatia \frac{3x}{x-4} ki te \frac{x-4}{x-4}.

$$\frac{3x\left(x-4\right)}{\left(x-4\right)^{2}}+\frac{5}{\left(x-4\right)^{2}}$$

Tā te mea he rite te tauraro o \frac{3x\left(x-4\right)}{\left(x-4\right)^{2}} me \frac{5}{\left(x-4\right)^{2}}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{3x\left(x-4\right)+5}{\left(x-4\right)^{2}}$$

Mahia ngā whakarea i roto o 3x\left(x-4\right)+5.

$$\frac{3x^{2}-12x+5}{\left(x-4\right)^{2}}$$

Whakarohaina te \left(x-4\right)^{2}.

$$\frac{3x^{2}-12x+5}{x^{2}-8x+16}$$

Whakaroha

$$\frac{3x^{2}-12x+5}{\left(x-4\right)^{2}}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x-4 me \left(x-4\right)^{2} ko \left(x-4\right)^{2}. Whakareatia \frac{3x}{x-4} ki te \frac{x-4}{x-4}.

$$\frac{3x\left(x-4\right)}{\left(x-4\right)^{2}}+\frac{5}{\left(x-4\right)^{2}}$$

Tā te mea he rite te tauraro o \frac{3x\left(x-4\right)}{\left(x-4\right)^{2}} me \frac{5}{\left(x-4\right)^{2}}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{3x\left(x-4\right)+5}{\left(x-4\right)^{2}}$$

Mahia ngā whakarea i roto o 3x\left(x-4\right)+5.

$$\frac{3x^{2}-12x+5}{\left(x-4\right)^{2}}$$

Whakarohaina te \left(x-4\right)^{2}.

$$\frac{3x^{2}-12x+5}{x^{2}-8x+16}$$