Whakaoti i te 3x/2x+8

$$\frac { 3 x } { 2 x + 8 }$$

Kimi Pārōnaki e ai ki x

$$\frac{6}{\left(x+4\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(2x^{1}+8\right)\frac{\mathrm{d}}{\mathrm{d}x}(3x^{1})-3x^{1}\frac{\mathrm{d}}{\mathrm{d}x}(2x^{1}+8)}{\left(2x^{1}+8\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(2x^{1}+8\right)\times 3x^{1-1}-3x^{1}\times 2x^{1-1}}{\left(2x^{1}+8\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{\left(2x^{1}+8\right)\times 3x^{0}-3x^{1}\times 2x^{0}}{\left(2x^{1}+8\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{2x^{1}\times 3x^{0}+8\times 3x^{0}-3x^{1}\times 2x^{0}}{\left(2x^{1}+8\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{2\times 3x^{1}+8\times 3x^{0}-3\times 2x^{1}}{\left(2x^{1}+8\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{6x^{1}+24x^{0}-6x^{1}}{\left(2x^{1}+8\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(6-6\right)x^{1}+24x^{0}}{\left(2x^{1}+8\right)^{2}}$$

Tango 6 mai i 6.

$$\frac{24x^{0}}{\left(2x^{1}+8\right)^{2}}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{24x^{0}}{\left(2x+8\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{24\times 1}{\left(2x+8\right)^{2}}$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$\frac{24}{\left(2x+8\right)^{2}}$$

Aromātai

$$\frac{3x}{2\left(x+4\right)}$$